SixBytes Institute Logo
SixBytesInstitute
CBSE & ICSE•Class 10 Mathematics•NCERT Solutions & Concepts•
Concept Topic GuideCBSE & ICSEClass 10MathematicsSome Applications of TrigonometryVerified Faculty Notes & Solutions

Some Applications of Trigonometry – Class 10 Maths Chapter 9: Heights & Distances

Class 10 Heights and Distances: angle of elevation, angle of depression, tower and building problems with solved examples for CBSE & ICSE.

8 students readUpdated 4 September 2026

Chapter 9: Some Applications of Trigonometry

9.1 Key Definitions

  • Line of Sight: The line drawn from the eye of the observer to the point being observed.
  • Angle of Elevation: The angle between the horizontal and the line of sight when looking upward at an object.
  • Angle of Depression: The angle between the horizontal and the line of sight when looking downward at an object.
Key Insight: The angle of elevation from point A to point B equals the angle of depression from point B to point A (alternate interior angles when a horizontal line is drawn at each point).

9.2 Problem-Solving Strategy

  1. Draw a clear diagram showing all given information.
  2. Identify the right triangle(s) in the figure.
  3. Label the known and unknown sides/angles.
  4. Choose the appropriate trigonometric ratio (sin, cos, or tan) based on which sides are involved.
  5. Solve the equation and find the required quantity.

9.3 Solved Examples

Example 1: Finding the height of a tower

A person standing 30 m away from the base of a tower observes the top at an angle of elevation of 60°. Find the height of the tower.

Solution

Let the height of the tower = h. In the right triangle formed:

tan 60° = h/30

√3 = h/30

h = 30√3 = 30 × 1.732 = 51.96 m

Example 2: Finding the distance

From the top of a 45 m high lighthouse, the angle of depression of a ship is 30°. Find the distance of the ship from the base of the lighthouse.

Solution

Let the distance of the ship from the base = d.

Angle of depression = 30° = angle of elevation from ship to top (alternate angles)

tan 30° = 45/d → 1/√3 = 45/d → d = 45√3 = 77.94 m

Common Values Used in Problems:
√2 ≈ 1.414    √3 ≈ 1.732    1/√3 ≈ 0.577
tan 30° = 1/√3    tan 45° = 1    tan 60° = √3

Indexed Topics & Examination Keywords

#heights and distances class 10#angle of elevation#angle of depression#trigonometry applications#NCERT maths#CBSE#ICSE#tower problems
SixBytes Academic Coaching • Shyampur & Premnagar

Aiming for 95%+ in CBSE / ICSE Board & Competitive Exams?

Join daily batches at SixBytes Institute for personalized mentoring, one-on-one doubt solving, and structured mock test series for Classes 9–12 & NDA.

Inquire on WhatsApp