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Concept Topic GuideCBSE & ICSEClass 10MathematicsCoordinate GeometryVerified Faculty Notes & Solutions

Coordinate Geometry – Class 10 Maths Chapter 7: Distance & Section Formula

Class 10 Coordinate Geometry notes: distance formula, section formula, midpoint, area of triangle, collinearity for CBSE & ICSE boards.

7 students readUpdated 4 September 2026

Chapter 7: Coordinate Geometry

7.1 Distance Formula

The distance between two points P(x₁, y₁) and Q(x₂, y₂) is:

PQ = √[(x₂ − x₁)² + (y₂ − y₁)²]

Example: Distance between A(3, 4) and B(7, 1):

AB = √[(7−3)² + (1−4)²] = √[16 + 9] = √25 = 5 units

Distance from origin: For point P(x, y): OP = √(x² + y²)

7.2 Section Formula

If a point P(x, y) divides the line segment joining A(x₁, y₁) and B(x₂, y₂) internally in the ratio m : n, then:

x = (mx₂ + nx₁) / (m + n)
y = (my₂ + ny₁) / (m + n)

7.3 Midpoint Formula

The midpoint of the line segment joining A(x₁, y₁) and B(x₂, y₂) is a special case of the section formula with m:n = 1:1:

Midpoint = ((x₁ + x₂)/2, (y₁ + y₂)/2)

7.4 Area of a Triangle

The area of a triangle with vertices A(x₁, y₁), B(x₂, y₂), and C(x₃, y₃) is:

Area = ½ |x₁(y₂ − y₃) + x₂(y₃ − y₁) + x₃(y₁ − y₂)|

If the area = 0, then the three points are collinear (lie on the same straight line).

Example: Find the area of triangle with vertices (1, 2), (4, 6), (7, 2).

Area = ½ |1(6−2) + 4(2−2) + 7(2−6)| = ½ |4 + 0 − 28| = ½ × 24 = 12 sq. units

Indexed Topics & Examination Keywords

#coordinate geometry class 10#distance formula#section formula#midpoint formula#area of triangle#collinearity#NCERT maths#CBSE#ICSE
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